(4x^2+2)+(7x^2+3)=71

Solution for (4x^2+2)+(7x^2+3)=71 equation:

Simplifying
(4x2 + 2) + (7x2 + 3) = 71

Reorder the terms:
(2 + 4x2) + (7x2 + 3) = 71

Remove parenthesis around (2 + 4x2)
2 + 4x2 + (7x2 + 3) = 71

Reorder the terms:
2 + 4x2 + (3 + 7x2) = 71

Remove parenthesis around (3 + 7x2)
2 + 4x2 + 3 + 7x2 = 71

Reorder the terms:
2 + 3 + 4x2 + 7x2 = 71

Combine like terms: 2 + 3 = 5
5 + 4x2 + 7x2 = 71

Combine like terms: 4x2 + 7x2 = 11x2
5 + 11x2 = 71

Solving
5 + 11x2 = 71

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 11x2 = 71 + -5

Combine like terms: 5 + -5 = 0
0 + 11x2 = 71 + -5
11x2 = 71 + -5

Combine like terms: 71 + -5 = 66
11x2 = 66

Divide each side by '11'.
x2 = 6

Simplifying
x2 = 6

Take the square root of each side:
x = {-2.449489743, 2.449489743}